Evaluate 3x 2 when x 5
WebExample: 3x^2-2x-1=0 (After you click the example, change the Method to 'Solve By Completing the Square'.) Take the Square Root. Example: 2x^2=18. Quadratic Formula. Example: 4x^2-2x-1=0. About quadratic equations Quadratic equations have an x^2 term, and can be rewritten to have the form: a x 2 + b x + c = 0. Need more problem types? Web2x3+7x2+2x-3=0 Three solutions were found : x = 1/2 = 0.500 x = -1 x = -3 Reformatting the input : Changes made to your input should not affect the solution: (1): "x2" was replaced by ... (2x-3)4x- (5x-1) (x+3) Final result : 3x2 - 26x + 3 Step by step solution : Step 1 :Equation at the end of step 1 : ( ( (2x - 3) • 4) • x) - (5x - 1 ...
Evaluate 3x 2 when x 5
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WebMay 8, 2016 · Explanation: −3x + 5. The value of the variable given is: x = − 2. −3x + 5 = − 3 ⋅ ( −2) +5. = 6 + 5. = 11. Answer link. WebEvaluate Using the Given Value -3x=2. −3x = 2 - 3 x = 2. Divide each term in −3x = 2 - 3 x = 2 by −3 - 3. −3x −3 = 2 −3 - 3 x - 3 = 2 - 3. Simplify the left side. Tap for more steps... x …
WebAlgebra. Evaluate (5/3)/2. 5 3 2 5 3 2. Multiply the numerator by the reciprocal of the denominator. 5 3 ⋅ 1 2 5 3 ⋅ 1 2. Multiply 5 3 ⋅ 1 2 5 3 ⋅ 1 2. Tap for more steps... 5 6 5 6. … WebAlgebra. Evaluate the Function f (5)=3x+2. f (5) = 3x + 2 f ( 5) = 3 x + 2. Replace the variable x x with 5 5 in the expression. f (5) = 3(5)+2 f ( 5) = 3 ( 5) + 2. Simplify the result. Tap for more steps...
WebEvaluate (2/5)^-3. ( 2 5)−3 ( 2 5) - 3. Change the sign of the exponent by rewriting the base as its reciprocal. (5 2)3 ( 5 2) 3. Apply the product rule to 5 2 5 2. 53 23 5 3 2 3. Raise 5 … WebFirst, evaluate h (3): h ( 3) = 3× ( 3)2 + a× 3 − 1. Simplify: h (3) = 27 + 3a − 1. h (3) = 26 + 3a. Now ... we are told that h (3) = 8: 8 = 26 + 3a. Swap sides: 26 + 3a = 8. Subtract 26 …
WebUnderstand the how and why See how to tackle your equations and why to use a particular method to solve it — making it easier for you to learn.; Learn from detailed step-by-step explanations Get walked through each step of the solution to know exactly what path gets you to the right answer.; Dig deeper into specific steps Our solver does what a calculator …
WebEnter the expression you want to evaluate. The Math Calculator will evaluate your problem down to a final solution. You can also add, subtraction, multiply, and divide and complete … bruce mau massive change networkWebTwo numbers r and s sum up to \frac{1}{3} exactly when the average of the two numbers is \frac{1}{2}*\frac{1}{3} = \frac{1}{6}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. evusheld fda eua fact sheetWebSolve for x -5=3x-2. −5 = 3x − 2 - 5 = 3 x - 2. Rewrite the equation as 3x−2 = −5 3 x - 2 = - 5. 3x−2 = −5 3 x - 2 = - 5. Move all terms not containing x x to the right side of the … evusheld faqWebHere are some examples: y=2x^2+1, y=3x-1, x=5, x=y^2. To graph a point, enter an ordered pair with the x-coordinate and y-coordinate separated by a comma, e.g., . To ... Algebra Calculator can also evaluate expressions that contain variables x and y. To evaluate an expression containing x and y, enter the expression you want to evaluate ... bruce m bird moWebNov 21, 2016 · This means we should let #f(x)=2# then solve for #x#, which is equal to #g(2)#. #f(x)=2" "=>" "x^5+3x-2=2# Continuing to solve yields. #x^5+3x-4=0# This may look impossible, but notice that the sum of the coefficients of each term is #0#, that is, #1+3-4=0#. This means that #x=1# is a solution. Dividing, we see that #(x … bruce maxwell dentistWeb9 hours ago · 11 of 25 Evaluate the expression 3h(5)+2g(-2), given functions g and h. g(x)=7-6x h(x)=7x^(2)-3x+6. Expert Answer. Who are the experts? Experts are tested by … bruce maxwell wikiWebTranscribed Image Text: Use the explicit formula, 4 - 2 n b - lim ΣΟΦ n→∞k=1 a (2x² (3x² - 2x+5) dx f (x) n dx = lim Σ f (a+k (b-a)) (b-a). n n→∞k=1 Set up the explicit formula by substituting the lower and upper limits for a and b. to evaluate the definite integral. bruce mayerson md smithtown ny